100 liters of a mixture contains 10% water and the rest milk. The amount of water that must be added so that the resulting mixture contains only 50% milk is
Solution(By Examveda Team)
80 Litter water required to convert mixture having 50% water.Total Mixture = 100 L.
Milk in Mixture is = 100 - 100 of 10% = 90L.
Water in Mixture is = 100 - 90 = 10L.
So water Required to convert a mixture to 50% milk and water is 90 - 10 = 80L
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200 litres of a mixture contains 15% water and the rest is milk. The amount
of milk that must be added so that the resulting mixture contains 87.5% milk
is:/
Total Mixture = 100 L
Milk in the mixture = 90% of 100 = 90 L.
Water = 10 L.
The amount of water to be added = 90 - 10 = 80 L.