3 solid cubes of sides 1 cm, 6 cm,and 8 cm are melted to form a new cube. What is the total Surface area of the cube so formed?
A. 101 sq.cm
B. 486 sq.cm
C. 81 sq.cm
D. 324 sq.cm
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Volume of first cube = 1 *1 *1 = 1 cubic cm.
Volume of second cube = 6 * 6 *6 = 216 cu cm.
Volume of third cube = 8 * 8 * 8 = 512 cub cm.
Then Volume of bigger cube = 512 + 1 + 216 = 729.
So, side of bigger cube = Cube root of 729 = 9 cm.
Surface area of cube = 6 * a^2 = 6 * 9 *9 = 486 sq. cm.