A and B are two container in which 6 liters and 3 liters of same type of acid of different concentration are kept. Same number of litre are emptied from each containers and is poured into other container and thus concentration of A and B becomes same. The quantity of acid emptied from each containers is?
A. 2
B. 1
C. 3
D. 3/4
Solution(By Examveda Team)
Let x is emptied⇒(3-x)/x = x/(6-x)
⇒18 - 6x -3x +x2 = x2
⇒18-9x = 0
⇒x = 2
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I can't understand plz explain with detels.
let container 1 have pure acid 6L
container 2 have pure water 3L
we take out x from both
concentration=acid content/ total amt of solution
so, 6-x / (6-x+x)= x/(3-x+x)
6-x/6=x/3
18-3x=6x
9x=18
x=2
Let x is emptied.
3-x/x = x/6-x
18 - 6x -3x +x^2 = x^2
18-9x = 0
x = 2
answer pls