A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone could do the work in
A. 5 days
B. 6 days
C. 9 days
D. 10 days
Answer: Option B
Solution(By Examveda Team)
1st Method: (A+B)'s one day's work = $$\frac{1}{3}$$ part (A+B) works 2 days together = $$\frac{2}{3}$$ part Remaining work = $$1 - \frac{2}{3}$$ = $$\frac{1}{3}$$ part $$\frac{1}{3}$$ part of work is completed by A in two days Hence, one day's work of A = $$\frac{1}{6}$$ Then, one day's work of B = $$\frac{1}{3} - \frac{1}{6}$$ = $$\frac{1}{6}$$ So, B alone can complete the whole work in 6 days. 2nd Method: (A+B)'s one day's % work = $$\frac{{100}}{3}$$ = 33.3% Work completed in 2 days = 66.6% Remaining work = 33.4% One day's % work of A = $$\frac{{33.4}}{2}$$ = 16.7% One day's work of B = 33.4 - 16.7 = 16.7% B alone can complete the work in, = $$\frac{{100}}{{16.7}}$$= 5.98 days
≈ 6 days.
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Comments ( 4 )
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1st method line nmber 5 can anyone explain
Remaining work main 1 Kahan Sy Aya aur A=1/6 Kahan sy aya
first method´s 5th line confuse
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