A bus takes 2.5 hrs more to cover a distance of 50 km when its speed is reduced by 10 kmph. Find its usual speed.
A. 10 kmph
B. 15 kmph
C. 20 kmph
D. 25 kmph
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Distance = 50 km
Original speed = S kmph (let)
New Speed = (S -10) kmph
Time difference = 2.5 hours
[50/(S-10) ] - 50/S = 2.5
{50* [S - S + 10] /(S *(S-10)) = 2.5
200 = S^2 - 10S
S^2 - 10S - 200 = 0
S^2 - 20S + 10S - 200 = 0
S = 20, -10.
Speed cannot be negative.
So, Original Speed = 20 kmph.
25km
can anyone give explanation please..
It is 20 km
c
Its 20km/hr