savio n
savio n
8 years ago

A does 1/2 work as B and C does 1/2 work as much as A and B together. If C alone can finish the work in 40 days the all will finish the work in?

A. 30 days

B. 13 1/2 days

C. 15 days

D. 20 days


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Comments ( 2 )

  1. Kumar Chandan
    Kumar Chandan :
    8 years ago

    C alone can finish the work in 40 days.
    (A + B)can do it in 20 days
    (A + B)s 1 days wok = 1/20.
    As 1 days work : Bs 1 days Work = 1/2 : 1 = 1:2.
    A's 1 day's work = (1/20) * (1/3) = (1/60). [Divide 1/20 in the raio 1:2] Bs 1 days work = (1/20) * (2/3) = 1/30
    (A+B+c)S 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40
    All the three together will finish it in 40/3 = 13 and 1/3 days.

  2. Kumar Chandan
    Kumar Chandan :
    8 years ago

    C can finish the work in 40 days.
    One day work of C = 1/40
    Now,
    A = 1/2 B
    B = 2A
    And,
    C = 1/2 ( A + B)
    C = 1/2 ( A + 2A) = 3/2 A =
    3/2 A = C
    3/2 A = 1/40
    A = 1/60
    B = 2 A = 2 * 1/60 = 1/30
    One day work of A, B and C together,
    = 1/60 + 1/30 + 1/40 = 9/120

    Thus, they all together can finish the work,
    = 10/9 = 13.33 days (Approx).

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