Chappa Santosh
Chappa Santosh
8 years ago

A part of the sum of Rs. 18000 was invested at 10% p.a.and the rest at 12%p.a. The interest received at the end of 3 years 4 months was 6560. Find the money lent at 10% p.a.

Solution(By Examveda Team)

Let X was invested at 10% p.a.

And (18000 - X) was invested at 12% p.a.

Time = 3 years and 4 months = 3 + 4/12 = 10/3 years.

For First Case,

i = ptr/100

i = [X * (10/3) * 10]/100

i = X/3   -------------------------------------------- (1)

Second case,

I = PTR/100

I = [(18000 - X) * (10/3) * 12]/100

I = 0.4 * (18000 - X)     --------------------------------------------------------- (2)

Now,

i + I = 6560

X/3 + 0.4 * (18000 - X) = 6560

X/3 + 7200 - 0.4X = 6560

0.33X - 0.4X = 6560 - 7200

- 0.07X = - 640

X = 9143.

Required Sum was Rs. 9143.


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Comments ( 2 )

  1. Indranil Mandal
    Indranil Mandal :
    8 years ago

    9600

  2. Rakesh
    Rakesh :
    8 years ago

    9600 (10%),8400 (12%)

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