A part of the sum of Rs. 18000 was invested at 10% p.a.and the rest at 12%p.a. The interest received at the end of 3 years 4 months was 6560. Find the money lent at 10% p.a.
Solution(By Examveda Team)
Let X was invested at 10% p.a.
And (18000 - X) was invested at 12% p.a.
Time = 3 years and 4 months = 3 + 4/12 = 10/3 years.
For First Case,
i = ptr/100
i = [X * (10/3) * 10]/100
i = X/3 -------------------------------------------- (1)
Second case,
I = PTR/100
I = [(18000 - X) * (10/3) * 12]/100
I = 0.4 * (18000 - X) --------------------------------------------------------- (2)
Now,
i + I = 6560
X/3 + 0.4 * (18000 - X) = 6560
X/3 + 7200 - 0.4X = 6560
0.33X - 0.4X = 6560 - 7200
- 0.07X = - 640
X = 9143.
Required Sum was Rs. 9143.
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9600
9600 (10%),8400 (12%)