A sells an article to B at a profit of 10% B sells the article back to A at a loss of 10%. In this transaction:
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
Answer: Option B
Solution(By Examveda Team)
First Method Let CP was 100 for A originally A sells article to B at 10% profit, CP for B = 100 + 10% of 100 = 110 Now, B sells it A again with loss 10% Now, CP for A this time = 110 - 10% of 110 = 99 A makes Profit = 110 - 99 = 11 %profit for A = $$\frac{{11 \times 100}}{{100}}$$ = 11% Second Method It could be easily shown by net percentage change graphic. 100(A) == 10%(Profit) ⇒110(B) == 10%(Loss) ⇒ 99(A) In this transaction A makes a profit of (110 - 99 = 11%) 11% [10% on selling to B and 1% profit on buying back from B]This Question Belongs to Arithmetic Ability >> Profit And Loss
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100 110
99=(110-11) 111*10%=11
11*100/100= 11% ansr
Any shortcut way
it should be 1% loss . i dont get 11% profit concept
He gives on article free for buying every.eighteen articles are also gives 16 2/3% discount find his discount percent.
IAM not understanding the percentage calculation difference for profit 10,n 10loss
Correct Answer = B. A makes a profit of 11%