Priti Saraf
Priti Saraf
8 years ago

A tank 'X' can be filled by an inlet pipe of circular cross section in 10 min. Another tank twice as big is filled in by 3 inlet pipes whose diameters are in the ratio 1:2:3. If the smallest pipe among these is four times as much in cross section as the inlet pipe of the tank 'X', find the time taken to fill the second tank. [Speed of water flowing into the second tank is half the speed of the water flowing into the first tank]

A. 5/14 min

B. 5/7 min

C. 5/6 min

D. 6/5 min

Answer: Option B

Solution(By Examveda Team)

If the ratio of diameters of 3 inlet pipes of second tank is 1:2:3, the ratio of their cross sectional areas will be 1:4:9. Suppose cross-sectional area of inlet pipe of first tank is k. Then the cross sectional areas of 3 pipes of second tank will be 4k, 16k and 36k respectively. Total cross sectional area of inlet pipes of second tank is 56k.
Time taken in filling the second tank is = 10* k/56k *2 *2 = 5/7 min.

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Comments ( 3 )

  1. Raghav Daga
    Raghav Daga :
    6 months ago

    why is 2 multiplied 2 times? because of the r square or something else?

  2. Ekta Gajwani
    Ekta Gajwani :
    2 years ago

    why 2 is multiplied 2 times ?

  3. Kajal Shaw
    Kajal Shaw :
    8 years ago

    Option B

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