Kritika Tyagi
Kritika Tyagi
10 years ago

After receiving two successive raises Harsh's salary became 15/8 times of his initial salary.By how much percent was the salary raised the first time if the second raise was twice as much as high(in percent) as the first?

A. 15%

B. 20%

C. 25%

D. 30%

Solution(By Examveda Team)

Let Initial salary was Rs. 100.
After two rais it become 15/8 i.e. (15*100)/8 = Rs. 187.5
Raise = 187.5 -100 = 87.5
Using formula,
[(first raise + 2nd rais) + (first raise *2nd raise)/100] = 87.5
X +2X + (2X^2)/100 = 87.53

300X + 2X^2 = 8750

X^2 + 150X = 4375

X^2 + 150X - 4375 = 0
X^2 + 175 X - 25X - 4375 =0

X = -175, 25 (Negative value is not possible)

So, X = 25%
Second Raise was 2X = 2*25 = 50%


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Comments ( 4 )

  1. Vishwani Reddy
    Vishwani Reddy :
    4 years ago

    @Tanzid It is the percentage raise and you misunderstood it as value raise

  2. Kumar Chandan
    Kumar Chandan :
    8 years ago

    @Tanzid you are making a mistake in understanding the question.
    @Leelanand, please give your explanation to have different explanation. Thank You.

  3. Leelanand Kumar
    Leelanand Kumar :
    8 years ago

    25% is the Right answer.... Nice one...

  4. Tanzid Ahmed
    Tanzid Ahmed :
    8 years ago

    Let bofore increasing Harsh salary was = 8, after increasing it is 15
    Now (15-8)= 7
    Since second percent is double than first, so amount ofcourse will be the double of second one than first one
    So
    x+2x=7...x=7/3
    Now, 7/3*100/8 = 30% (approximately)

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