Examveda
Examveda

Determine Output:
void main()
{
      char *p;
      printf("%d %d", sizeof(*p), sizeof(p));
}

A. 1 1

B. 1 2

C. 2 1

D. 2 2

Answer: Option B

Solution(By Examveda Team)

The sizeof() operator gives the number of bytes taken by its operand. P is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.


This Question Belongs to C Program >> C Miscellaneous

Join The Discussion

Comments ( 3 )

  1. Bhagvat Giri
    Bhagvat Giri :
    3 years ago

    size of pointer is 8 bytes for 64 bit OS
    size of pointer is 4 bytes for 32 bit OS

  2. Roshan Meshram
    Roshan Meshram :
    3 years ago

    when i executed this code, it gave an output :1 4

  3. Katheeja Beevi
    Katheeja Beevi :
    6 years ago

    When I execute the code, I got output as 1 8

Related Questions on C Miscellaneous