Determine output:
void main()
{
int c = - -2;
printf("c=%d", c);
}
void main()
{
int c = - -2;
printf("c=%d", c);
}A. 1
B. -2
C. 2
D. Error
Answer: Option C
Solution(By Examveda Team)
In this C program, the expression- -2 involves the use of the unary minus operator (-) applied twice to the number 2.
- The first
- operator negates the number 2, resulting in -2.- The second
- operator negates -2, which effectively makes it positive again, resulting in 2.
So, the variable
c is assigned the value 2, and the output of the printf statement is c=2, which corresponds to Option C.
This Question Belongs to C Program >> Operators And Expressions
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Comments ( 3 )
Related Questions on Operators and Expressions
What does the ++ operator do in C when applied to a variable?
A. Decrements by 1
B. Adds 1
C. Doubles the value
D. Leaves it unchanged
The answer given here is actually right. It's not the unary operator.Actually it is - (-2) and not --2.
c is wrong option. because binary operator works on two operand. and unary operator works on single variale like ++a or --a.
Dnt guide wrong and before post question's answer plz also execute and check.
https://www.onlinegdb.com/online_c_compiler
any one who are confused about that concept please check the code of program with run window.
No. Answer is error. we cant have unary increment or decrement operator used on numbers directly. we can store the number in a variable and then increment or decrement it . Here it gives Compilation Error.