HCF of 2472,1284 and a 3rd number ‘N’ is 12. If LCM of these three numbers is 2^3*3^2*5^1*103*107, then ‘N’?

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Kumar Chandan :

2 years ago

HCF of the numbers * LCM of the numbers = Multiplication of the numbers.
(12)*(2^3*3^2*5*103*107) = 2472* 1284*N;
Hence,
N = {(12)*(2^3*3^2*5*103*107)}/2472*1284;
Or, N = 3*5.

HCF of the numbers * LCM of the numbers = Multiplication of the numbers.

(12)*(2^3*3^2*5*103*107) = 2472* 1284*N;

Hence,

N = {(12)*(2^3*3^2*5*103*107)}/2472*1284;

Or, N = 3*5.