If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys to do the same type of work will be :
A. 5 days
B. 4 days
C. 6 days
D. 7 days
Answer: Option B
Solution(By Examveda Team)
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2,.
Solving these two equations, we get : x = 1/100 and y = 1/200 .
(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
So, 15 men and 20 boys can do the work in 4 days.
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Ans is 4
1st condition = 10(6m+8b) here m= men & b= boys
2nd condition = 2(26m+48b)
3rd condition = X(15m+20b) here X= required time
Since the all conditions are same.
We get from 1st & 2nd conditions,
60m+80b = 52m + 96b
Or, 8m = 16b
Or, m = 2b
Now from 1st & 3rd conditions,
(60×2b)+80b = X(15×2b+20b)
Or, 200b = X (50b)
Or, X = 200b/50b
Or, X = 4 days
b) 4 days
give me a more easy method... its to long..