In a family there are several brothers and sisters. Every 2 boys have brothers as many as sisters and each girl has 2 brothers less than twice as many brothers as sisters. Now find the number of boys and girls.
A. 8 , 6
B. 6 , 4
C. 6 , 8
D. 12 , 10
Answer: Option A
Solution(By Examveda Team)
Let B be the number of brothers and S be the number of sisters in the family. Consider any two boys. They would be having (B - 2) brothers (excluding the two). But this number is equal to the number of sisters they have. Therefore, B - 2 = S or , B - S = 2 ............(1) Each girl will have (S - 1) sisters. Twice the number of sisters = 2(S - 1). Since, each girl has twice as many brothers as sisters, we have, 2(S-1)-2 = B 2S - 4 = B ........... (2) Substituting, eqn (2) in Eqn (1), we get 2S - 4 - S = 2 S = 6 On substituting S = 6 in eqn (1) , we get B - 6 = 2 B = 8.Related Questions on Puzzle
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