In Java byte, short, int and long all of these are
A. signed
B. unsigned
C. Both of the above
D. None of these
Answer: Option A
Solution(By Examveda Team)
In Java, byte, short, int, and long are all signed integer data types.Here's the breakdown:
Option A: signed - This option is correct. byte, short, int, and long are all signed integer data types in Java, which means they can represent both positive and negative whole numbers.
Option B: unsigned - This option is not correct. Java does not have built-in unsigned integer data types. Unlike some other programming languages, all integer data types in Java are signed by default.
Option C: Both of the above - This option is not correct because only Option A is true. Java integer data types are signed, not unsigned.
Option D: None of these - This option is not correct because Option A is the correct answer. Java's byte, short, int, and long are all signed integer data types.
So, in Java, byte, short, int, and long are all signed integer data types.
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Which of the following is not a valid identifier for a Java variable?
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byte: 8-bit signed integer. Can hold values from -128 to 127.
short: 16-bit signed integer. Can hold values from -32,768 to 32,767.
int: a 32-bit signed integer. Can hold values from -2,147,483,648 to 2,147,483,647.
long: a 64-bit integer. Can hold really big numbers (-2^63 to 2^63–1).
The answer will be signed because these data types consist of both positive and negative values.
THANK YOU
may i know the explanation of this question please.
Only "String" is unsigned, signed data means the data has to be declared before we use it.