Joy Shaha
Joy Shaha
7 years ago

A train daily overtakes a cyclist at a fixed time and fixed place. One day cyclist is late by 25 minutes and hence train overtakes him at a point 6 km earlier than the fixed place. Find the speed of the train, if the speed of the cyclist is 12 km/hr.


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  1. Kumar Chandan
    Kumar Chandan :
    7 years ago

    Let the train daily overtakes the cyclist at a fixed point A and a fixed time.
    One day cyclist late by 25 minutes, So, cyclist will rach at fixed point by 25 minutes late.
    But train overtakes cyclist 6 km before the fixed point.
    The time taken by cyclist to reach at fixed point after crossing the train,
    = 6/12 = 1/2 hours = 30 min.
    Thus, Difference between time taken by cyclist usual and on late day at Point B , 6 km before the fixed point = 30 - 25 = 5 min.
    So, Train will take 5 minutes to reach at fixed point from B.
    So, Ratio of speed = 6:1.
    Speed of the train = 72 kmph.

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