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Rs. 2100 is lent at compound interest of 5% per annum for 2 years. Find the amount after two years.

A. Rs. 2300

B. Rs. 2315.25

C. Rs. 2310

D. Rs. 2320

E. None of these

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{We}}\,{\text{can}}\,{\text{use}}\,{\text{formula}}\,{\text{of}}\,{\text{compound}}\,{\text{interest}} \cr & A = P \times {\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]^n} \cr & A = 2100 \times {\left[ {1 + \left( {\frac{5}{{100}}} \right)} \right]^2} \cr & A = 2100 \times {\left[ {\frac{{105}}{{100}}} \right]^2} \cr & A = \frac{{ {2100 \times 11025} }}{{10000}} \cr & {\text{Hence,}}\,{\text{Amount}}\,A = Rs.\,2315.25 \cr} $$

This Question Belongs to Arithmetic Ability >> Interest

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Comments ( 2 )

  1. Rakesh Sahoo
    Rakesh Sahoo :
    2 years ago

    How it's 105

  2. Praveen Kumar
    Praveen Kumar :
    3 years ago

    We can use formula of compound interest;
    A = P*[1+ (r/100)]n
    A = 2100*[1+(5/100)]2
    A = 2100*[105/100]2
    A = (2100*11025)/10000
    Hence, Amount, A = Rs. 2315.25.

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