When a number is successively divided by 7, 5, and 4 , it leaves remainders of 4, 2, and 3 respectively. What will be the respective remainders when the smallest such number is successively divided by 8, 5 and 6?
A. 5, 0, 3
B. 2, 2, 4
C. 3, 0, 3
D. 2, 4, 2
Solution(By Examveda Team)
The number would be in the form of (7X + 4) as when this number is divide by 7, will give remainder 4.
Now, we will try hit and trial method to obtained the number.
Put, X = 17, then
7X + 4 = 7 *17 + 4 = 119 + 4 = 123.
Now, when
123 divided by 7, gievs quotient = 17, remainder = 4.
17 divided by 5, quotient = 3, remainder = 2
3 divide by 4 gives remainder 3.
So far first condition satisfied . Now,
123 divide by 8, quotient = 15, remainder = 3
15 divided by 5, quotient = 3, remainder = 0
3 divided by 6, remainder = 3.
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Comments ( 3 )
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In solution, HIT and TRIAL method has been used. It means you have to choose a proper value for X. So, it totally depends on you common sense what you choose for the value of X. @Kunal
How can you consider to select only 17
17 when divided by 5 how can the remainder be 3?????