Umar
Umar
9 years ago

When a number is successively divided by 7, 5, and 4 , it leaves remainders of 4, 2, and 3 respectively. What will be the respective remainders when the smallest such number is successively divided by 8, 5 and 6?

A. 5, 0, 3

B. 2, 2, 4

C. 3, 0, 3

D. 2, 4, 2

Solution(By Examveda Team)

The number would be in the form of (7X + 4) as when this number is divide by 7, will give remainder 4.

Now, we will try hit and trial method to obtained the number.

Put, X = 17, then

7X + 4 = 7 *17 + 4 = 119 + 4 = 123.
Now, when

123 divided by 7, gievs quotient = 17, remainder = 4.
17 divided by 5, quotient = 3, remainder = 2

3 divide by 4 gives remainder 3.

So far first condition satisfied . Now,

123 divide by 8, quotient = 15, remainder = 3
15 divided by 5, quotient = 3, remainder = 0

3 divided by 6, remainder = 3.


 


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Comments ( 3 )

  1. Kumar Chandan
    Kumar Chandan :
    8 years ago

    In solution, HIT and TRIAL method has been used. It means you have to choose a proper value for X. So, it totally depends on you common sense what you choose for the value of X. @Kunal

  2. Kunal Madankar
    Kunal Madankar :
    8 years ago

    How can you consider to select only 17

  3. Vishal Chandola
    Vishal Chandola :
    8 years ago

    17 when divided by 5 how can the remainder be 3?????

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