A thief steals a car at 2:30 pm and drive it at 60 km/h the theft is discover at 3 pm and the owner sets off another car at 75 km/ h when will be overtakes thief
A. 4.30 pm
B. 5.00 pm
C. 5.15 pm
D. 5.30 pm
Answer: Option B
Solution(By Examveda Team)
Suppose he thief is overtaken x hrs after 2.30 p.m.Then, distance covered by he thief in x hrs. = distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2)
15x = 75/2
x = 5/2 hrs.
So, the thief is overtaken at 5 p.m.
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