Percentage - Aptitude MCQ Questions and Solutions with Explanations

Answer: Option C

Amount paid to car owner = 90% of 85% of Rs. 325000
= Rs. $$\left( {\frac{90}{{100}} \times \frac{85}{100} \times 325000} \right)$$
= Rs. 248625
∴ Required difference :
= Rs. (325000 - 248625)
= Rs. 76375

Answer: Option C

Let the number of valid votes be x
Then,
60% of x = 255000
⇒ x = $$\left( {\frac{{255000 \times 100}}{{60}}} \right)$$
⇒ x = 425000
Number of invalid votes :
= (500000 - 425000)
= 75000
∴ Required percentage :
= $$\left( {\frac{{75000 \times 100}}{{500000}}} \right)$$    %
= 15%

Answer: Option B

x = 80% of y
⇒ x = $$\frac{80}{100}$$y
⇒ $$\frac{y}{x}$$ = $$\frac{5}{4}$$
⇒ $$\frac{y}{2x}$$ = $$\frac{5}{8}$$
∴ Required percentage :
$$\eqalign{ & = \left( {\frac{y}{{2x}} \times 100} \right)\% \cr & = \left( {\frac{5}{8} \times 100} \right)\% \cr & = 62\frac{1}{2}\% \cr} $$

Answer: Option D

Let the original price of tea be Rs. x per kg and that of sugar be Rs. y per kg
Then,
5x + 8y = 172
⇒ 15x + 24y = 516.....(i)
And, 120% of 5x + 110% of 8y = 199.20
⇒ 600x + 880y = 19920
⇒ 15x + 22y = 498 .....(ii)
Subtracting (ii) from (i), we get 2y = 18 or y = 9
Putting y = 9 in (i), we get: x = 20

Answer: Option C

Let the fare for a full ticket be Rs. x and the boarding charges be Rs. y per ticket.
Then, fare for a half-ticket :
= 75% of Rs. x = Rs. $$\frac{3x}{4}$$
$$\eqalign{ & \therefore \left( {x + y} \right) + \left( {\frac{3}{4}x + y} \right) = 1440 \cr & \Rightarrow \frac{{7x}}{4} + 2y = 1440 \cr & \Rightarrow 7x + 8y = 5760 ..... (i) \cr & {\text{And, 2}}\left( {x + y} \right) + \left( {\frac{3}{4}x + y} \right) = 2220 \cr & \Rightarrow \frac{{11x}}{4} + 3y = 2220 \cr & \Rightarrow 11x + 12y = 8880 ..... (ii) \cr} $$
Solving (i) and (ii), we have, x = 480, y = 300