Percentage - Aptitude MCQ Questions and Solutions with Explanations

Answer: Option E

Let the required number of chicken be x
Then, 65% of x = 47775
$$\eqalign{ & \Rightarrow \frac{{65}}{{100}}x = 47775 \cr & \Rightarrow x = \frac{{47775 \times 100}}{{65}} \cr & \Rightarrow x = 73500 \cr} $$

Answer: Option A

Let the number be x
Then,
$$\eqalign{ & \Rightarrow x = 125 = 37\frac{1}{2}\% {\text{ of }}x \cr & \Rightarrow x - 125 = \frac{{75}}{2} \times \frac{1}{{100}} \times x \cr & \Rightarrow x - 125 = \frac{{3x}}{8} \cr & \Rightarrow x - \frac{{3x}}{8} = 125 \cr & \Rightarrow \frac{{5x}}{8} = 125 \cr & \Rightarrow x = \left( {\frac{{125 \times 8}}{5}} \right) \cr & \Rightarrow x = 200 \cr & \therefore 25\% {\text{ of 200}} \cr & = \left( {\frac{{25}}{{100}} \times 200} \right) \cr & = 50 \cr} $$

Answer: Option E

Let the maximum marks be x.
Then,
$$\eqalign{ & \left( {40 - 4} \right)\% {\text{ of }}x = 261 \cr & \Rightarrow 36\% {\text{ of }}x = 261 \cr & \Rightarrow \frac{{36}}{{100}}x = 261 \cr & \Rightarrow x = \left( {\frac{{261 \times 100}}{{36}}} \right) \cr & \Rightarrow x = 725 \cr} $$

Answer: Option D

$$\frac{x}{100}$$ × y = $$\frac{4}{5}$$ × 80
⇒ xy = 64 × 100
⇒ xy = 6400

Answer: Option C

Total number of fruits = (14 + 23) = 37
Let x oranges be removed.
Then,
70% of (37 - x) = 14
⇒ 7 (37 - x) = 140
⇒ 37 - x = 20
⇒ x = 17