ExamVeda
Login
Home

Problems On H.C.F And L.C.M - Aptitude MCQ Questions and Solutions with Explanations

Problems On H.C.F And L.C.M MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Problems On H.C.F And L.C.M with easy and logical explanations. Problems On H.C.F And L.C.M MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-10 section-1

Each section contains 100 MCQs on Problems on H.C.F and L.C.M .
91
The product of two numbers is 396 × 576 and their LCM is 6336. Find their HCF = ?
Discuss
Answer & Solution
Answer: Option A
Solution:
We, know that
(a × b) = (HCF and LCM)
396 × 576 = HCF × 6336
HCF = 36
92
The greatest number, which when subtracted from 5834, gives a number exactly divisible by each of 20, 28, 32 and 35 is ?
Discuss
Answer & Solution
Answer: Option B
Solution:
LCM of (20, 28, 32, 35)
4 × 5 × 7 × 8 = 1120
LCM = (20, 28, 32, 35) = 1120
∴ 1120 divided by 20, 28, 32, 35 completely
∴ Let x be subtracted from 5834
∴ 5834 - x = 1120
⇒ x = 5834 - 1120 = 4714
93
21 mango trees, 42 apple trees and 56 orange trees have to be planted in rows such that each row contains the same numbers of trees of one variety only. Minimum number of row in which the trees may be planted is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
For the minimum number of rows, the numbers of trees in each row must be the maximum.
Number of trees in each row = HCF of 21, 42, 56 = 7
Hence number of rows
$$\eqalign{ & {\text{ = }}\left( {\frac{{21 + 42 + 56}}{7}} \right) \cr & = \frac{{119}}{7} \cr & = 17 \cr} $$
94
The greatest possible length which can be used to measure exactly the lengths 7m, 3m 85cm, 12m 95cm is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Required length = HCF of 700cm, 385cm and 1295cm = 35cm
95
Two numbers are in the ratio 3:4. Their LCM is 84. The greater number is ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let numbers are = 3x & 4x respectively
LCM = 84 (given)
∴ LCM number = common factor (other factors)
x × 3 × 4 = 12x
⇒ 12x = 84
⇒ x = 7
∴ Number are = 3x = 7 × 3 = 21
4x = 7 × 4 = 28
greater number is 28
96
The HCF and LCM of two numbers are 12 and 924 respectively. Then the number of such pair is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
HCF = 12
Let numbers are 12x and 12y respectively
LCM ⇒ 12xy = 924(given)
⇒ xy = 77
⇒ Possible pairs are
= (1 × 77) (7 × 11)
∴ Only two pairs are possible
97
The LCM of two numbers is 520 and their HCF is 4. If one of the numbers is 52, then the other number is = ?
Discuss
Answer & Solution
Answer: Option A
Solution:
LCM = 520
HCF = 4
one number = 52
Let other number is y
52y = 4 × 520
⇒ y = 40
98
The capacity of two pots is 120 litres and 56 litres respectively. Find the capacity of a container which can exactly measure the contents of the two pots = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Required capacity = HCF of 120 litres and 56 litres
= 8 litres = 8000 cc [∴ 1 litres = 1000 cc]
99
A daily wage labourer was engaged for a certain number of days for Rs. 5750, but being absent on some of those days he was paid only Rs. 5000. What was his maximum possible daily wage ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Try to solve these kind of question by option
Because of his being absent he was paid Rs. 750 less.
Now check with option.
Since maximum possible daily wages is asked so it will be Rs. 250

OR :
Maximum possible daily wage
= HCF of Rs. 5750 and Rs. 5000
= Rs. 250
100
The product of two numbers is 2028 and their HCF is 13. The number of such of pair is = ?
Discuss
Answer & Solution
Answer: Option B
Solution:
HCF = 13 (given)
Let number are 13x & 13y respectively
$$\eqalign{ & {\text{Also given}} \cr & 13x \times 13y = 2028 \cr & 13 \times 13 \times xy = 2028 \cr & xy = \frac{{2028}}{{13 \times 13}} = 12 \cr & \therefore {\text{Possible pairs are}} \cr & {\text{ = }}\left( {1,12} \right)\left( {3,4} \right) \cr} $$
Only two pair are possible