Applied Mechanics And Graphic Statics MCQ Questions & Answers

11

The centre of gravity of a quadrant of a circle lies along its central radius at a distance of

A) 0.2 R B) 0.4 R C) 0.3 R D) 0.6 R

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Answer & Solution

Answer: Option D

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12

If the angular distance, 0 = 2t³ - 3t², the angular acceleration at t = 1 sec. is

A) 1 rad/sec² B) 4 rad/sec² C) 6 rad/sec² D) 12 rad/sec²

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Answer & Solution

Answer: Option C

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13

If g₁ and g₂ are the gravitational accelerations on two mountains A and B respectively, the weight of a body when transported from A to B will be multiplied by

A) g₁ B) g₂ C) $$\frac{{{{\text{g}}_1}}}{{{{\text{g}}_2}}}$$ D) $$\frac{{{{\text{g}}_2}}}{{{{\text{g}}_1}}}$$

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Answer & Solution

Answer: Option D

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14

The vertical reaction at the support ‘A’ of the structure shown in below figure, is
Applied Mechanics and Graphic Statics mcq question image

A) 1 t B) 2 t C) 3 t D) 3.5 t

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Answer & Solution

Answer: Option C

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15

The member which does not carry zero force in the structure shown in below figure, is
Applied Mechanics and Graphic Statics mcq question image

A) ED B) DC C) BC D) BD

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Answer & Solution

Answer: Option D

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16

The motion of a bicycle wheel is

A) Translatory B) Rotary C) Rotary and translatory D) Curvilinear

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Answer & Solution

Answer: Option C

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17

Dimensional formula of Universal Gravitational constant G is-

A) M^-1L³T^-2 B) M^-1L²T^-2 C) M^-2L³T^-2 D) M^-2L²T^-2

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Answer & Solution

Answer: Option D

Solution:

The dimensional formula of the Universal Gravitational constant G is derived from Newton's law of universal gravitation which states that the force of attraction between two point masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:
F=G⋅m₁⋅m₂/r²
Where:
F is the force of attraction
G is the Universal Gravitational constant
m₁ and m₂ are the masses of the objects
r is the distance between the objects
To determine the dimensional formula of G, we can rearrange the formula as:
G=F⋅r²/m₁⋅m₂
Now, let's analyze the dimensions:
Force (F) has the dimensional formula: M¹L¹T^-2
Distance (r) has the dimensional formula: L¹
Mass (m₁ and m₂) has the dimensional formula: M¹
Substituting these dimensions into the rearranged formula, we get:
G=(M¹L¹T^-2)⋅(L¹)²/M¹⋅M¹
G=M^-2L²T^-2
Therefore, the correct dimensional formula of Universal Gravitational constant G is M^-2L²T^-2.

18

Effect of a force on a body depends upon its

A) Direction B) Magnitude C) Position D) All the above

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Answer & Solution

Answer: Option D

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19

The following statement is one of the laws of Dynamic friction

A) The force of friction always acts in a direction opposite to that in which a body is moving B) The magnitude of the kinetic friction bears a constant ratio to the normal reaction between two surfaces. The ratio being slightly less than that in the case of limiting friction C) For moderate speeds the force of friction remains constant but decreases slightly with the increase of speed D) All the above

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Answer & Solution

Answer: Option D

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20

If $$l$$ is the span of a light suspension bridge who's each cable carries total weight (w) and the central dip is y, the horizontal pull at each support, is

A) $$\frac{{{\text{w}}l}}{{4{\text{y}}}}$$ B) $$\frac{{{\text{w}}l}}{{8{\text{y}}}}$$ C) $$\frac{{{\text{w}}l}}{{2{\text{y}}}}$$ D) $${\text{w}}l$$

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Answer & Solution

Answer: Option B

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Applied Mechanics And Graphic Statics MCQ Questions & Answers | Civil Engineering