Concept of relative Speed, Average Speed and Acceleration and their applications

Concept of Relative Speed

Movement of one body with respect to another moving body is called the relative speed of each other.

Case 1:
Two bodies are moving in opposite direction at a speed S1 and S2 respectively. Then
Relative speed = S1 + S2

Case 2:
Two bodies are moving in same direction at a speed S1 and S2 respectively. Then
Relative speed= |S1 - S2|
In this case, we take positive value of difference of speeds.

Acceleration:

Acceleration is defined as rate of change of speed. Acceleration can be positive (speed increases) or negative (speed decreases, also known as deceleration). Unit of acceleration is m/S2
Final speed= Initial speed + Acceleration × time.

Average speed:

If a certain distance is covered in parts at different speeds, the average speed is given by
Average speed = $$\frac{{{\text{Total}}\,{\text{distance}}\,{\text{covered}}}}{{{\text{Total}}\,{\text{time}}\,{\text{taken}}}}$$
Suppose a car goes from A to B at an average speed S1 and then comes back from B to A an average speed of S2. If you have to find the average speed of the whole journey, then average speed is given by,
Average speed = $$\frac{{2{S_1} \times {S_2}}}{{{S_1} + {S_2}}}$$
Average speed = $$\frac{{2 \times {\text{products}}\,{\text{of}}\,{\text{speeds}}}}{{{\text{sum}}\,{\text{of}}\,{\text{speeds}}}}$$

Example 1:
Ramu climbs a mountain with 10 km/h speed and returns with 20 km/h speed then what is his average speed?

Solution:
Average speed
$$\eqalign{ & = \frac{{2{S_1} \times {S_2}}}{{{S_1} + {S_2}}} \cr & = \frac{{2 \times 10 \times 20}}{{10 + 20}} \cr & = 13\frac{1}{3}\,{\text{km/h}} \cr} $$

Example 2:
A car travels at 60 km/h from Mumbai to Poona and at 120 km/h from Poona to Mumbai. What is the average speed of the car for the entire journey?

Solution:
Average speed
$$\eqalign{ & = \frac{{2{S_1} \times {S_2}}}{{{S_1} + {S_2}}} \cr & = \frac{{2 \times 60 \times 120}}{{180}} \cr & = 80\,{\text{km/h}} \cr} $$

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