If in the following figure (not to the scale), ∠ACB = 135° and the radius of the circle is 2√2 cm, then the length of the chord AB is

Solution (By Examveda Team)

$$\eqalign{ & {\text{Hence }}A{B^2} = {\left( {2\sqrt 2 } \right)^2} + {\left( {2\sqrt 2 } \right)^2} \cr & A{B^2} = 8 + 8 \cr & A{B^2} = 16 \cr & AB = \sqrt {16} \cr & AB = 4 \cr} $$