In a circle with centre O, a diameter AB is produced to a point P lying outside the circle and PT is a tangent to the circle at the point C on it. If ∠BFT = 36°, then is the measure of ∠BCP?
A. 24°
B. 18°
C. 36°
D. 27°
Answer: Option D
Solution (By Examveda Team)
∠BCP = ?
∠PCO = 90° (PT is a Tangent)
In ΔPCO
∠COB = 180° - (36° + 90°) = 54°
Let ∠OCB = ∠OBC = θ (∵ OC = OB)
In ΔOCB
2θ = 180°- 54°
θ = 63°
∠BCP = 90° - 63° = 27° Answer
This Question Belongs to Arithmetic Ability >> Geometry
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In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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