The product of two numbers is 2008 and their HCF is 13. The number of such pairs is = ?
A. 1
B. 2
C. 3
D. 4
Answer: Option B
Solution(By Examveda Team)
Let the numbers be 13a and 13bThen, 13a × 13b = 2028
ab = 12
Now, co - primes with product 12 are (1, 12) and (3, 4)
So, the required numbers are (13 × 1, 13 × 12) and (13 × 3, 13 × 4)
Clearly, there are 2 such pairs
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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