3x + 4y = 10 . . . . . . . (i)
-x + 2y = 0 . . . . . . . (ii)
On solving both the equation
3(2y) + 4y = 10
10y = 10
y = 1
∴ x = 2 × 1 = 2
∴ Solution (a, b) = (2, 1)
∴ a + b = 2 + 1 = 3
44.
Find equation of the perpendicular to segment joining the points A(0, 4) and B(-5, 9) and passing through the point P. Point P divides segment AB in the ratio 2 : 3.
Parallelogram ABCD
AD || BC
Slope of line AD (m) = Slope of line BC
Slope of line BC $$ = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{4 - 3}}{{ - 1 + 2}} = 1$$
Slope of AD = 1
Equation of line AD ⇒
y - y1 = m(x - x1)
x1 = 5, y1 = 0
y - 0 = 1(x - 5)
y = x - 5
47.
If ax - 4y = -6 has a slope of $$ - \frac{3}{2}.$$ What is the value of a?