Chemical Engineering Thermodynamics MCQ Questions & Answers | Chemical Engineering

A. Two temperatures only

B. Pressure of working fluid

C. Mass of the working fluid

D. Mass and pressure both of the working fluid

A. $$\frac{{{{\text{T}}_2} - {{\text{T}}_1}}}{{{{\text{T}}_2}}}$$

B. $$\frac{{{{\text{T}}_2} - {{\text{T}}_1}}}{{{{\text{T}}_1}}}$$

C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_2}}}$$

D. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$

A. $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$

B. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$

C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$

D. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_2}}}$$

A. 100, 000 kW

B. 160, 000 kW

C. 200, 000 kW

D. 320, 000 kW

A. 0

B. 1

C. 2

D. 3

A. Violates second law of thermodynamics

B. Involves transfer of heat from low temperature to high temperature

C. Both A and B

D. Neither A nor B

A. P + F - C = 2

B. C = P - F + 2

C. F = C - P - 2

D. P = F - C - 2

A. ΔH = 0 and ΔS = 0

B. ΔH ≠ 0 and ΔS = 0

C. ΔH ≠ 0 and ΔS ≠ 0

D. ΔH = 0 and ΔS ≠ 0

A. Not a function of its pressure

B. Not a function of its nature

C. Not a function of its temperature

D. Unity, if it follows PV = nRT

A. Isobaric

B. Isothermal

C. Isentropic

D. Isometric