Answer & Solution
Answer: Option D
Solution:
The middle letter remained unaltered in the code. Let us label the five letters before the middle letter as well as those after it, from 1 to 5. Then, the code contains the letters of each group in the order 5, 4, 1, 3, 2.
Thus, we have :
ESTABLISHED => BAETSLDEIHS
12345/12345 => 54132/54132