Answer & Solution
Answer: Option E
Solution:
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Speed of C on Day 2} \cr
& = 45 \text{ km/hr} \cr
& = \left(45\times\frac{5}{18}\right) \text{m/sec} \cr
& = \frac{25}{2} \text{ m/s} \cr
& = 12.5 \text{ m/s} \cr} $$
