Answer & Solution
Answer: Option E
Solution:
$$\eqalign{
& \text{Total number of teachers in:} \cr
& \text{A → } \frac{14}{100}\times4500 = 630\cr
& \text{B → } \frac{16}{100}\times4500 = 720\cr
& \text{C → } \frac{28}{100}\times4500 = 1260\cr
& \text{D → } \frac{15}{100}\times4500 = 675\cr
& \text{E → } \frac{21}{100}\times4500 = 945\cr
& \text{F → } \frac{6}{100}\times4500 = 270\cr} $$
|
A |
B |
C |
D |
E |
F |
| Males |
200 |
400 |
600 |
100 |
500 |
100 |
| Females |
430 |
320 |
660 |
575 |
445 |
170 |
Female teacher in D = 575
Total number of teacher in A
= 200 + 430
= 630
∴ Required percentage
$$\eqalign{
& = \left(\frac{575}{630}\times100\right)\% \cr
& = \frac{5750}{63}\% \cr
& = 91.2\% \cr
& \approx 90\% \cr} $$
