Answer & Solution
Answer: Option E
Solution:
$$\eqalign{
& \text{Number of students in:} \cr
& \text{A → } \frac{12}{100}\times6000 = 720 \cr
& \text{B → } \frac{9}{100}\times6000 = 540 \cr
& \text{C → } \frac{26}{100}\times6000 = 1560 \cr
& \text{D → } \frac{18}{100}\times6000 = 1080 \cr
& \text{E → } \frac{29}{100}\times6000 = 1740 \cr
& \text{F → } \frac{6}{100}\times6000 = 360 \cr} $$
Number of boys in:
A → 500
B → 400
C → 900
D → 600
E → 1200
F → 100
Number of girls in:
A → 720 - 500 = 220
B → 540 - 400 = 140
C → 1560 - 900 = 660
D → 1080 - 600 = 480
E → 1740 - 1200 = 540
F → 360 - 100 = 260
Let (number of girls in A) be $$x$$% of number of students in B.
Then,
$$\eqalign{
& 220 = \frac{x}{100}\times540 \cr
& \Rightarrow x = \frac{220\times100}{540} \cr
& \Rightarrow x = \frac{1100}{27} \cr
& \Rightarrow x = 40.7 \cr
& \Rightarrow x \approx 40\% \cr} $$
