Answer & Solution
Answer: Option B
Solution:
Average number of students qualified from C and D
$$\eqalign{
& = \frac{1}{2}\left(2250+2000\right) \cr
& = \frac{4250}{2} \cr
& = 2125 \cr} $$
Average number of students appeared from C and D
$$\eqalign{
& = \frac{1}{2}\left(3250+2500\right) \cr
& = \frac{5750}{2} \cr
& = 2875 \cr
& \therefore \text{ Required %} \cr
& = \left(\frac{2125}{2875}\times100\right)\% \cr
& = \left(\frac{85}{115}\times100\right)\% \cr
& = \frac{1700}{23}\% \cr
& = 73.91\% \cr} $$
