Solution:
Number of candidates clearing the exam from state D in
$$\eqalign{
& 2008 → \left(1.83\times\frac{60}{100}\right)\text{lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = \frac{1.83\times3}{5}\text{ lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = \frac{5.49}{5}\text{ lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = 1.10\text{ lakhs} \cr
& 2009 → \left(2.01\times\frac{56}{100}\right)\text{lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = \frac{2.01\times14}{25}\text{ lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = \frac{28.14}{25}\text{ lakhs} \cr
& \,\,\,\,\,\,\,\,\,\,\, = 1.12\text{ lakhs} \cr} $$
In rest of the years it is clearly less.
So, it is maximum in the year 2009
