63.
Consider points P and Q in the x-y plane, with P = (1, 0) and Q = (0, 1). The line integral \[2\int\limits_{\rm{P}}^{\rm{Q}} {\left( {{\rm{xdx}} + {\rm{ydy}}} \right)} \]    along the semicircle with the line segment PQ as its diameter

64.
A surface S(x, y) = 2x + 5y - 3 is integrated once over a path consisting of the points that satisfy (x + 1)2 + (y - 1)2 = √2. The integral evaluates to

65.
Let w = f(x, y), where x and y are functions of t. Then, according to the chain rule, \[\frac{{{\rm{dw}}}}{{{\rm{dt}}}}\] is equal

66.
For the parallelogram OPQR shown in the sketch, \[\overline {{\rm{OP}}} = {\rm{a\hat t}} + {\rm{b\hat j}}\]   and \[\overline {{\rm{OR}}} = {\rm{c\hat t}} + {\rm{d\hat j}}{\rm{.}}\]   The area of the parallelogram is
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69.
If for non-zero x, \[{\rm{af}}\left( {\rm{x}} \right) + {\rm{bf}}\left( {\frac{1}{{\rm{x}}}} \right) = \frac{1}{{\rm{x}}} - 25\]      where a ≠ b then \[\int\limits_1^2 {{\rm{f}}\left( {\rm{x}} \right){\rm{dx}}} \]   is

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