If the length of the rectangle is increased by 230%, its area becomes 828 sq. cm and perimeter 162 cm . What is the perimeter of the original rectangle?

Solution(By Examveda Team)

Let original area was 100 sq. cm.
If length of square increase by 230% then its area also increases by 230%.

Increase in area = 230% So,

Area become, (100 + (230% of 100)) = 330 sq. cm.

Given, New area = 828 sq. cm.
Now, comparing,
330 = 828
1 = 828/330
100 = (828*100)/330 = 251 sq. cm (Approx.)

Area of square = a*a
a*a = 251
a = 15.84 cm
Original Perimeter = 4a = 4 * 15.84 = 64 cm (Approx.)