In one litre of a mixture of alcohol and water,water is 30%. The amount of alcohol that must be added to the mixture so that the part of water in the mixture becomes 15% is
A. 1000ml
B. 700ml
C. 300ml
D. 900ml
Answer: Option A
Solution(By Examveda Team)
Water = 30% in 1 liter = 0.3 liter = 300 ml.Alcohol = 700 ml
Total new mixture be x ml.
15% of x = 300
x = 2000 ml.
Alcohol added = 2000 - 700 - 300 = 1000 ml.
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I need ans in link up method
Water = 30% in 1 liter = 0.30 liter.
Alcohol = 0.7 liter.
Let x amount alcohol added.
Alcohol = (0.7 +x)
Now, according to question,
15% of (1 + x) = 0.3
15 + 15x = 15
15x = 30 - 15
x = 15/15 = 1 liter = 1000 ml.
In one Lt mixture of alcohol and water, % of water = 30%
the amount of water = 30% of 1 Lt
= 30 / 100 *1
=0.3 Lt
amount of alcohol = 1 - 0.3 = 0.7 Lt
let we should mix X Lt of alcohol to make % of water as 15 %
total amount of mixture = (X + 1) Lt
therefore
0.3 / (X + 1) * 100 = 15
30 = 15 (X + 1)
X + 1 = 2
X = 2 - 1 = 1 Lt
thus we must add 1 Lt alcohol to give mixture. means 1000 ml
Correct Answer = A ( 1000 ml )