Six boys A, B, C, D,E abd F are marching in a line.They are arranged according their height. The tallest are being at the back and shortest in front.
. F is between B and A
. E is shorter than D but taller than C, who is taller than A
. E and F have two boys between them
. A is not the shortest among them all.
(a) where is E ?
(b) who is tallest?
(c) if we start counting from the shortest .which boy is fourth in the line?
(d) who is shortest?
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i have got it acc to question
D > E > C > A > F > B
not understood kumar chandan.According to me the pattern is like that BFACED
F is between B and F.
For this arrangement would be either
BFA or AFB.
F is between B and A . E is shorter than D but taller than C, who is taller than A .
Arrangement would be like this
DECA.
Given, there are two boys between E and f.
So final arrangement would be
DECAFB. (As given, A is not shortest in all.)
E is the second tallest in all. So posses second position from left.
D is tallest among all and B is shortest.
C will occupy fourth position.