Nasri S
Nasri S
8 years ago

Six boys A, B, C, D,E abd F are marching in a line.They are arranged according their height. The tallest are being at the back and shortest in front.
. F is between B and A
. E is shorter than D but taller than C, who is taller than A
. E and F have two boys between them
. A is not the shortest among them all.
(a) where is E ?
(b) who is tallest?
(c) if we start counting from the shortest .which boy is fourth in the line?
(d) who is shortest?


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Comments ( 3 )

  1. Archna
    Archna :
    8 years ago

    i have got it acc to question
    D > E > C > A > F > B

  2. Sushma Saroj
    Sushma Saroj :
    8 years ago

    not understood kumar chandan.According to me the pattern is like that BFACED

  3. Kumar Chandan
    Kumar Chandan :
    8 years ago

    F is between B and F.
    For this arrangement would be either
    BFA or AFB.
    F is between B and A . E is shorter than D but taller than C, who is taller than A .
    Arrangement would be like this
    DECA.
    Given, there are two boys between E and f.
    So final arrangement would be
    DECAFB. (As given, A is not shortest in all.)
    E is the second tallest in all. So posses second position from left.
    D is tallest among all and B is shortest.
    C will occupy fourth position.

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