The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.

A) 33....

if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+3)=2(x+3)+10
or, x=10
so the fathers present age =(3x+3)=(3*10+3)years =33years..

33

Let the present age of son be x yrs.
Fathers age = 3 + 3x

now, three years hence,

3 + (3+ 3x) = 10 + 2 (x+3)
x = 10

Fathers present age = 3 + 3x
= 3 + 3(10)
= 33 yrs ans

A)33

fathers age is f = 3s+3
son age is=s
from next statement
hence 3 year,
father=f+3,
son=s+3,
f+3=10+2(s+3)
from first statement we know that,
3s+3+3=10+2(s+3),
solving this,
son age s=10,
fathers age is = 3*10+3=33.

ans = A

(A) 33
at present f=3+3s ..(1)
3 yrs hence
f=f+3 and s=s+3
f+3=10+2(s+3)
f+3=10+2s+6
from1
3+3s+3=10+2s+6
s=10
f=3+3*s
f=3+3*10=33