X and Y are two stations 630 km apart. P starts from X and moves towards Y at 90km/hr. Q starts from Y at the same time and moves towards X at 120km/hr. Find the extra distance travelled by Q when they meet.
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X ________________________________________________Y
Total Distance = 630 km.
Let Q travels M km to meet P.
P need to travel = (630 - M) km.
Speed of the Q = 120 kmph.
Speed of the P = 90 kmph.
Time taken by Q to reach meeting point = Time taken by P to reach same place
M/120 = (630 -M)/90
90 M = 120 * 630 - 120 M
90 M + 120 M = 120 * 630
210 M = 120 * 630
M = 360 Km.
So, Q travels 360 km and P travels (630 - 360) = 270 km to meet.
Thus, Q travels = 360 - 270 = 90 km more than P.