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15th term of A.P., x - 7, x - 2, x + 3, ........ is
Answer & Solution
Correct Answer:
Option
A
an = a + (n - 1) × d
where,
d = x - 2 -x + 7 = 5,
a = x - 7
⇒ a15 = (x - 7) + (15 - 1) × 5
⇒ a15 = (x - 7) + 14 × 5
⇒ a15 = x - 7 + 70
⇒ a15 = x + 63
where,
d = x - 2 -x + 7 = 5,
a = x - 7
⇒ a15 = (x - 7) + (15 - 1) × 5
⇒ a15 = (x - 7) + 14 × 5
⇒ a15 = x - 7 + 70
⇒ a15 = x + 63
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