2 Ants start simultaneously from 2 ant holes towards each other. The 1st ant covers 8% of the distance between the two ant holes in 3hrs, the 2nd ant covers 7/120th of distance in 2hr 30 mins. Find the speed( feet/hr) of the 2nd ant if 1st ant travelled 800 feet to the meeting point?
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Speed of ant1=(8/3)/100 of hole per hour
Speed of ant2=(7/120)/2,5=(7/3)/100 of hole per hour
If ant1 goes 800 metres to meeting point then ant2 goes 700 metres.
Total distance makes 1500 metres.
Speed of ant2=(7/3)/100 of hole per hour it makes (7/3)/100 * 1500= 35 metres per hour.