ExamVeda
Login
Home
Square Root and Cube Root
?

$$99 \times 21 - \root 3 \of ? = 1968$$

Answer & Solution
Correct Answer: Option A
$$\eqalign{ & {\text{Let,}} \cr & {\text{ }}99 \times 21 - \root 3 \of x = 1968 \cr & {\text{Then,}} \cr & \Leftrightarrow 2079 - \root 3 \of x = 1968 \cr & \Leftrightarrow \root 3 \of x = 2079 - 1968 \cr & \Leftrightarrow \root 3 \of x = 111 \cr & \Leftrightarrow x = {\left( {111} \right)^3} \cr & \Leftrightarrow x = 1367631 \cr} $$
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.