A 12 kΩ resistor is in series with a 0.02 µF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 ∠0° mA, what is the source voltage expressed in polar form?
A. 45.6 V
B. 411.3 V
C. 0.411 V
D. 4.11 V
Answer: Option D
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Related Questions on RC Circuits
When the frequency of the source voltage decreases, the impedance of a parallel RC circuit
A. Increases
B. Decreases
C. Does not change
D. Decreases to zero
V=IZ
Z=Sqr(R^2+Xc^2)---------- (a)
Xc=(1/(2*pi*f*C))
By solving we get,
Xc=6631.45 ohms
Now put values in (a) and by solving we get,
Z = 13710.44 ohms
To find voltage,
V=IZ=13710.44*0.3 mA
=4.11 volts