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A 12 k resistor is in series with a 0 02...

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RC Circuits
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A 12 kΩ resistor is in series with a 0.02 µF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 ∠0° mA, what is the source voltage expressed in polar form?

Answer & Solution
Correct Answer: Option D
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1 Comment
Afifa
Afifa 3 years ago
V=IZ
Z=Sqr(R^2+Xc^2)---------- (a)
Xc=(1/(2*pi*f*C))
By solving we get,
Xc=6631.45 ohms
Now put values in (a) and by solving we get,
Z = 13710.44 ohms
To find voltage,
V=IZ=13710.44*0.3 mA
=4.11 volts
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