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A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 ∠0° mA. The source voltage, expressed in polar form, is

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Correct Answer: Option A
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2 Comments
Jadoon Khan
Jadoon Khan 2 years ago
R=12000
XL=2pi fL
=2*3.14*8000*90^-3
=4521.6
Z=12000+j4521.6
Z=√12000^2+4521.6^2
=12823.60
O°=tan^-1 4521.6/12000
=20.6
V=12823.6*0.3^-3
=3.84°20.64
ANKIT MAURYA
ANKIT MAURYA 7 years ago
Q ka solve ti dete nhi ho