A 12 kHz voltage is applied to a 0.33 µF capacitor, and 200 mA of rms current is measured. What is the value of the voltage?
A. 8 V
B. 80 V
C. 800 V
D. 0.88 V
Answer: Option A
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C=.33
F=12×10^3 hz
I=200mA
V=???
Xc=1/(2×3.13×F×C)
=1/(2×3.12×12×10^3×.33×10^-6)
=1000/24.86
=40.22 ohm
Hear..Xc=Z
I=V/Z
200×10^-3=V/40.22
V=0.2×40.22
=8.04volt
Please give the solution step wise