A 12 V source has an internal resistance of 90 Ω. If a load resistance of 20 Ω is connected to the voltage source, the load power, PL, is
A. 2.38 mW
B. 2.38 W
C. 238 mW
D. 23.8 W
Answer: Option C
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Related Questions on Circuit Theorems and Conversions
What is the Thevenin equivalent (VTH and RTH) for the circuit given?
A. 6.4 V, 422 Ω
B. 6.4 V, 560 Ω
C. 6.4 V, 680 Ω
D. 30 V, 422 Ω
A. 676 mA
B. 245 mA
C. 431 mA
D. 75 mA
By Voltage divider rule
VL = (Vs * Rs)/ sum of resistances
= (12*20)/ (20+90) = 2.18V
To find power
P = V^2/R
PL = (VL^2)/RL
PL = (2.18^2)/20 = 237.62 mW => 238 mW
P=sq I . R