A 1.5 kΩ resistor and a coil with a 2.2 kΩ inductive reactance are in series across an 18 V ac source. The power factor is
A. 564
B. 0.564
C. 6.76
D. 55.7
Answer: Option B
A. 564
B. 0.564
C. 6.76
D. 55.7
Answer: Option B
If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit
A. Doubles
B. Halves
C. Remains constant
D. Cannot be determined without values
When the frequency is decreased, the impedance of a parallel RL circuit
A. Increases
B. Decreases
C. Remains constant
D. Is not a factor
Z=√(r^2+XL^2)=2663.
P.f = cosq = r/z=1500/2663
0.564.
P.f= R/IV
p.f = R/XL
|z| = sqrt(1500^2+2200^2) = 2663
Angle = inverse tan(22001500) = 55.7
Power Factor = Cos(55.7) = 0.564